固定卡片删除功能的描述正确的是（）。-刷刷题APP

【简答题】完成单词。 1. z r num. 2. ne num. 3. tw num. 4. thr num. 5. f num. 6. f ve num． 7. s x num. 8. s v n num. 9. t num. 10. n ne num. 11. t l ph ne n. 12. c d n. 13....

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【单选题】A．单臂卡环 B．环形卡环 C．固定卡环 D．锻丝上返卡环 E．锻丝下返卡环

A.

患者，女，47岁，

缺失，可摘局部义齿修复，基牙

靠近缺隙侧倒凹大，这种情况下，

上可设计（）

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【单选题】有如下事件过程：Private Sub Form_Load() Show Dim Arr() As Variant Arr = Array(1, 3, 5, 7, 9, 11, 13, 15) Call converse(Arr) For i = 0 To 7 Print arr(i); Next iEnd Sub 以上程序的功能是，通过调用Converse过程，将数组Arr中的元素逆序存放并输出...

A.

Private Sub converse(dim a() as Variant ) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub

B.

Private Sub converse(dim a() as Variant) Dim T Dim J As Integer J = (LBound(A) + UBound(A)) / 2 For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub

C.

Private Sub converse(a() As Variant) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub

D.

Private Sub converse(a() As Variant) Dim T Dim J As Integer J = Int((LBound(A) + UBound(A)) / 2) For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub

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