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【简答题】

原生动物的胞囊在什么条件下会形成?它有什么特点和功能?

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参考答案:
参考解析:
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刷刷题刷刷变学霸
举一反三

【多选题】下列原生动物可以通过动物接种法进行检查的有:

A.
伊氏锥虫
B.
马媾疫锥虫
C.
胎儿毛滴虫
D.
弓形虫
E.
巴贝斯虫
F.
泰勒虫 G. 组织滴虫

【多选题】胆管细胞囊腺癌CT表现包括().

A.
实质部分为高密度
B.
囊壁厚薄不均
C.
可见囊壁结节
D.
囊内液体密度
E.
病变显著强化

【单选题】有如下事件过程:Private Sub Form_Load() Show Dim Arr() As Variant Arr = Array(1, 3, 5, 7, 9, 11, 13, 15) Call converse(Arr) For i = 0 To 7 Print arr(i); Next iEnd Sub 以上程序的功能是,通过调用Converse过程,将数组Arr中的元素逆序存放并输出...

A.
Private Sub converse(dim a() as Variant ) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
B.
Private Sub converse(dim a() as Variant) Dim T Dim J As Integer J = (LBound(A) + UBound(A)) / 2 For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
C.
Private Sub converse(a() As Variant) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
D.
Private Sub converse(a() As Variant) Dim T Dim J As Integer J = Int((LBound(A) + UBound(A)) / 2) For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub

【多选题】监控平台有哪些功能?

A.
管理设备
B.
用户权限管理
C.
数据流管理
D.
录像存储管理
E.
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