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【单选题】
利用MATLAB符号计算功能计算数列极限,下列结论中错误的是 (本题10.0分)
A.
MATLAB的符号计算不能直接计算数列极限
B.
如果将数列极限转化为x趋于正无穷大时的函数极限，且该函数极限存在，则原数列极限也一定存在
C.
MATLAB可以通过编写程序代码，验证已知的数列极限
D.
如果将数列极限转化为x趋于正无穷大时的函数极限，且该函数极限不存在，则原数列极限也一定不存在
参考答案：
参考解析：
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【单选题】有如下事件过程：Private Sub Form_Load() Show Dim Arr() As Variant Arr = Array(1, 3, 5, 7, 9, 11, 13, 15) Call converse(Arr) For i = 0 To 7 Print arr(i); Next iEnd Sub 以上程序的功能是，通过调用Converse过程，将数组Arr中的元素逆序存放并输出...
A.
Private Sub converse(dim a() as Variant ) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
B.
Private Sub converse(dim a() as Variant) Dim T Dim J As Integer J = (LBound(A) + UBound(A)) / 2 For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
C.
Private Sub converse(a() As Variant) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
D.
Private Sub converse(a() As Variant) Dim T Dim J As Integer J = Int((LBound(A) + UBound(A)) / 2) For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
【单选题】用于耐火防护的材料产品，应按等效工程使用条件的燃烧试验满足耐火极限不低于 1h的要求，且耐火温度不低于( )。
A.
100℃
B.
500℃
C.
1000℃
D.
2000℃