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【简答题】

阅读理解。 My friend, Emma Daniels, spent the summer of 1974 traveling in Israel. During her month-long stay in Jerusalem she often went to a café called Chocolate Soup. It was run by two men, one of whom-Alex-used to live in Montreal. One morning when Emma went in for coffee, while chatting with her new friend Alex, she mentioned that she had just finished the book she was reading and had nothing else to read. Alex said he had a wonderful book she might like, and that he'd be happy to lend it to her. As he lived just above the café, he quickly ran up to get it. The book he handed to Emma just minutes later was Markings, a book by a former Secretary-General of the United Nations (UN). Emma had never read it, nor had she ever bought a copy. But, when she opened it up, she was floored to see her own name and address inside the cover in her own handwriting (笔迹). It turned out that the summer before, at a concert back in Montreal, Emma had met a Californian who was in town visiting friends. They decided to exchange (交换) addresses, but neither of them had any paper. The man opened up a book he was carrying in his backpack (背包) and asked Emma to write her name and address inside. When he returned to California, he left the book behind in Montreal, and his friend Alex kept it. When Alex later moved to Jerusalem, he took the book along. 1. Alex lent Emma the book, Markings, _____. A. to show his friendliness to her B. to show his interest in reading C. to tell her about the importance of the UN D. to let her write her name and address inside 2. How did Emma feel the moment she opened the book? A. Pleased. B. Satisfied. C. Worried. D. Surprised. 3. We can learn from the text that the Californian _____. A. met Emma at a concert B. invited Emma to a concert C. introduced Emma to his friend D. left Emma his backpack 4. Who was supposed to be the first owner of the book? A. An official of the UN. B. A coffee shop owner. C. A friend of the author's. D. Alex's friend from California.

题目标签:交换背包
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参考解析:
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举一反三

【单选题】01背包的一维状态转移方程是(i表示物品编号,j表示背包容量)

A.
dp[i] = max(dp[j], dp[j-w[i]]+v[i])
B.
dp[j] = max(dp[i], dp[j-w[i]]+v[i])
C.
dp[j] = max(dp[j], dp[j-w[i]]+v[i])
D.
dp[j] = max(dp[j], dp[j-w[j]]+v[j])

【单选题】交换度是针对()而言。

A.
分子筛上被交换的阳离子
B.
溶液中的阳离子
C.
分子筛上被交换的阴离子
D.
溶液中的阴离子

【单选题】决定肺部气体交换方向的主要因素是( )。

A.
气体的分压差
B.
气体与血红蛋白的亲和力
C.
气体分子质量的大小
D.
呼吸膜对气体的通透性
E.
以上都不是

【单选题】在户外最常用的背包上肩的方法是( )。

A.
高处上肩法
B.
提拉上肩法
C.
弓步上肩法
D.
下蹲上肩法

【多选题】生产决定着分配、交换和消费的

A.
水平和结构
B.
社会性质
C.
物质对象
D.
具体方式

【多选题】交换提入票据退票的正当理由包括()。

A.
印鉴不符
B.
存款不足
C.
付款人账号户名有误
D.
大小写金额不符

【单选题】完全背包的状态转移方程是()

A.
dp[i] = max(dp[j], dp[j-w[i]]+v[i])
B.
dp[j] = max(dp[i], dp[j-w[i]]+v[i])
C.
dp[j] = max(dp[j], dp[j-w[i]]+v[i])
D.
dp[j] = max(dp[j], dp[j-w[j]]+v[j])
相关题目:
【单选题】01背包的一维状态转移方程是(i表示物品编号,j表示背包容量)
A.
dp[i] = max(dp[j], dp[j-w[i]]+v[i])
B.
dp[j] = max(dp[i], dp[j-w[i]]+v[i])
C.
dp[j] = max(dp[j], dp[j-w[i]]+v[i])
D.
dp[j] = max(dp[j], dp[j-w[j]]+v[j])
【单选题】交换度是针对()而言。
A.
分子筛上被交换的阳离子
B.
溶液中的阳离子
C.
分子筛上被交换的阴离子
D.
溶液中的阴离子
【单选题】决定肺部气体交换方向的主要因素是( )。
A.
气体的分压差
B.
气体与血红蛋白的亲和力
C.
气体分子质量的大小
D.
呼吸膜对气体的通透性
E.
以上都不是
【单选题】在户外最常用的背包上肩的方法是( )。
A.
高处上肩法
B.
提拉上肩法
C.
弓步上肩法
D.
下蹲上肩法
【单选题】背包()
A.
backpack
B.
headache
C.
backache
【多选题】生产决定着分配、交换和消费的
A.
水平和结构
B.
社会性质
C.
物质对象
D.
具体方式
【多选题】交换提入票据退票的正当理由包括()。
A.
印鉴不符
B.
存款不足
C.
付款人账号户名有误
D.
大小写金额不符
【单选题】完全背包的状态转移方程是()
A.
dp[i] = max(dp[j], dp[j-w[i]]+v[i])
B.
dp[j] = max(dp[i], dp[j-w[i]]+v[i])
C.
dp[j] = max(dp[j], dp[j-w[i]]+v[i])
D.
dp[j] = max(dp[j], dp[j-w[j]]+v[j])