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【单选题】
一患者
缺失，戴局部义齿一周后复诊，主诉咀嚼功能差，无其他不适。主要原因是（）。
A.
基托过度伸展
B.
基托伸展不够
C.
人工牙牙尖斜度大
D.
人工牙咬合低
E.
基牙负荷重
参考答案：
参考解析：
刷刷题刷刷变学霸
举一反三
【单选题】可摘义齿人工牙脱落的原因不包括
A.
人工塑料牙与基托之间有异物
B.
缺牙间隙太多
C.
人工塑料牙与基托胶接面太小
D.
人工塑料牙向嵴面没有粗糙面
E.
人工塑料牙向嵴面没有用单体溶胀
【单选题】有如下事件过程：Private Sub Form_Load() Show Dim Arr() As Variant Arr = Array(1, 3, 5, 7, 9, 11, 13, 15) Call converse(Arr) For i = 0 To 7 Print arr(i); Next iEnd Sub 以上程序的功能是，通过调用Converse过程，将数组Arr中的元素逆序存放并输出...
A.
Private Sub converse(dim a() as Variant ) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
B.
Private Sub converse(dim a() as Variant) Dim T Dim J As Integer J = (LBound(A) + UBound(A)) / 2 For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
C.
Private Sub converse(a() As Variant) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
D.
Private Sub converse(a() As Variant) Dim T Dim J As Integer J = Int((LBound(A) + UBound(A)) / 2) For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
【单选题】义齿基托树脂下列描述错误的是
A.
自凝树脂可用于制作腭护板
B.
冬天为加快热凝树脂面团期的形成，可将调和物放在火焰上加热
C.
自凝树脂的机械性能整体上不如热凝树脂
D.
自凝树脂调和后，一般在糊状期塑形
E.
自凝树脂残余单体量较热凝树脂高
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