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【简答题】
在考生文件夹下,给定程序FILL.C的功能是: 查找n在数组a中最后一次出现的位置(数组首元素的位置为零)。 例如:如果a数组中的元素为:1,5,2,5,6,8,7,4,3,0, 当n=5时,程序的输出结果为:5 is No.3 。 当n=10时,程序的输出结果应为:10 not found !。 #include
void main( ) { int a[10]={1,5,2,5,6,8,7,4,3,0}; int i,k,n,f=0; scanf("%d",&n); for(i=0;i<10;i++) /************found************/ if(___(1)___) { f=1; /************found************/ ___(2)___; } if(f) printf("%d is No. %d\n", n,k); else printf(" %d not found !\n",n); }
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参考解析：
刷刷题刷刷变学霸
举一反三
【单选题】有如下事件过程：Private Sub Form_Load() Show Dim Arr() As Variant Arr = Array(1, 3, 5, 7, 9, 11, 13, 15) Call converse(Arr) For i = 0 To 7 Print arr(i); Next iEnd Sub 以上程序的功能是，通过调用Converse过程，将数组Arr中的元素逆序存放并输出...
A.
Private Sub converse(dim a() as Variant ) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
B.
Private Sub converse(dim a() as Variant) Dim T Dim J As Integer J = (LBound(A) + UBound(A)) / 2 For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
C.
Private Sub converse(a() As Variant) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub
D.
Private Sub converse(a() As Variant) Dim T Dim J As Integer J = Int((LBound(A) + UBound(A)) / 2) For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub