蛋白质的一级结构决定空间结构，空间结构决定功能。-刷刷题APP

【判断题】蛋白质的结构涉及一级结构及三维结构。

A.

正确

B.

错误

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【单选题】蛋白质属于（）

A.

植物化学物

B.

宏量营养素

C.

微量元素

D.

宏量元素

E.

抗氧化营养素

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【单选题】构成蛋白质一级结构的化学键是

A.

氨基酸的α-羧基与相邻氨基酸α-氨基脱水缩合成肽键

B.

肽键与肽键之间形成氢键

C.

侧链间的氢键

D.

次级键

E.

游离氨基与羧基形成肽键

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【单选题】有如下事件过程：Private Sub Form_Load() Show Dim Arr() As Variant Arr = Array(1, 3, 5, 7, 9, 11, 13, 15) Call converse(Arr) For i = 0 To 7 Print arr(i); Next iEnd Sub 以上程序的功能是，通过调用Converse过程，将数组Arr中的元素逆序存放并输出...

A.

Private Sub converse(dim a() as Variant ) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub

B.

Private Sub converse(dim a() as Variant) Dim T Dim J As Integer J = (LBound(A) + UBound(A)) / 2 For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub

C.

Private Sub converse(a() As Variant) Dim T For i = LBound(A) To UBound(A) T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub

D.

Private Sub converse(a() As Variant) Dim T Dim J As Integer J = Int((LBound(A) + UBound(A)) / 2) For i = LBound(A) To J T = a(i) a(i) = a(UBound(A) - i) a(UBound(A) - i) = T Next i End Sub

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