C
|
C
|
|
原式=
=
2)原式=
|
证明:log2(4sin 1110°)=log2[4sin(3×360°+30°)]=log2(4sin 30°)=log22=1. ∴log2(4sin1110°)=1. |
C
|
|
∵cos(-300°)=cos300°=cos(360°-60°)=cos60°=
故选C. |
(1)sin2120°+cos180°+tan45°-cos2(-330°)+sin(-210°) =(sin60°)2-cos(0°)+tan45°-(cos30°)2+sin(30°) =
=
(2)
=
=-cosα |
B
|